Networking

Networking

Postby sheetal13 » Sun May 18, 2014 11:07 pm

Assume that each character code consists of 8 bits.the number of characters that can be transmited per second through an syncronus serial lineat 2400 baud rate and with two stop bits is
a.109
b.216
c.218
d.219
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Re: Networking

Postby luvthelyf » Mon Sep 14, 2015 11:53 am

Answer should be (c)218.
Explaination: In asynchronous transmission start and stop bits both are necessary.
So number of bytes transferred per second is:
2400/(1 start bit + 8 character bits + 2 stop bits)
= (int)2400/11 = 218
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